第五题

戏唱故梦2025-05-31

代码

a = set('ababcdabca')
x = {x for x in a if x not in 'ab'}
print(a - x)
print(a | x)
print(a ^ x)
print(a & x)

{'b', 'a'}
{'d', 'a', 'c', 'b'}
{'b', 'a'}
{'c', 'd'}